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divide 15x^5-21x^4+18^2 / 3x^2
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\[\Large \frac{15x^5}{3x^2} - \frac{21x^4}{3x^2} + \frac{18x^2}{3x^2}\]
basically...you can divide EACH term of the numerator by the denominator
after I do that will that be the answer? Or will I have to simplify it more?
that's pretty much it
Okay well I got 5x^3-7x^2+6x. Does that sound right?
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no x in 6x...
x^2 just cancels out
Oh okay, I questioned myself on that part. Tnks so much :)
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