What is an equation of the circle whose center is ( -3,1) and whose radius is 10 ?

a. (x+3)^2 + ( y-1)^2 = 10
b. (x+3) ^2 + ( y-1)^2 = 100
c. ( x-3)^2 + (y+1)^2 = 10
d. (x-3)^2 + (y+1)^2 = 100

Question

What is an equation of the circle whose center is ( -3,1) and whose radius is 10 ?

a. (x+3)^2 + ( y-1)^2 = 10
b. (x+3) ^2 + ( y-1)^2 = 100
c. ( x-3)^2 + (y+1)^2 = 10
d. (x-3)^2 + (y+1)^2 = 100

anonymous · Answer

center (h,k)

(x-h)+(y-k)=r^2

anonymous · Answer

i dont understand .... whats h and k ? @LagrangeSon678

anonymous · Answer

h and k is the center.

In your case, your h is the x coordinate, -3.

your k is the y coordinate, 1

anonymous · Answer

just replace h with -3 and k with 1 in the equation of the circle:(x-h)^2+(y-k)^2=r^2