$$\int \int_R \sin (x - y) dA. R = [(x,y) | 0 \le x \le \pi / 2, 0 \le y \le \pi / 2]$$

can someone tell me what that meant o.O

Question

$$\int \int_R \sin (x - y) dA. R = [(x,y) | 0 \le x \le \pi / 2, 0 \le y \le \pi / 2]$$

can someone tell me what that meant o.O

anonymous · Answer

its a double integral

anonymous · Answer

the limits for x and y are provided, it straight forward

anonymous · Answer

this is mulitvariable calculus, its not something that would show up in calc 2 or integral calc

lgbasallote · Answer

what does "multivariable calculus" mean exactly?

lgbasallote · Answer

and why is it not under integral calculus?

zarkon · Answer

latex tip...use $$\iint$$    \iint

when writing a double integral

lgbasallote · Answer

ohh...was it that obvious haha

zarkon · Answer

$$\iint_R \sin (x - y) dA\,\,\,\,\,\,\,\,\,\,\, R = \{(x,y) | 0 \le x \le \pi / 2, 0 \le y \le \pi / 2\}$$

zarkon · Answer

$$=\int\limits_{0}^{\pi/2} \int\limits_{0}^{\pi/2} \sin (x - y) dx\,dy$$

lgbasallote · Answer

but what does R mean? i mean wht it symbolizes

zarkon · Answer

$R$ is the region is the $xy$ plane that you are integrating over.

lgbasallote · Answer

and dA? differential area?

zarkon · Answer

yes...typically it is written $dA=dx dy=dydx$

lgbasallote · Answer

ohhh thanks :DD