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By sketching a suitable pair of graphs, show that the equation
cosec x = (1/2)x+1
where x is in radians, has a root in the intervale 0
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@.Sam.
This is Graph from -Pi to Pi
How could you do this by plugging in values, since the calc doesn't have any cosec values?
1/Sin(x)=csc(x)
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so it becomes 1/sin(x) = 1/2(x) +1?
pretty much yeah
but which is the y and which is the x value?
plot cscx=y and the line y= 0.5x+1 on same graph...they will intersect in the interval given, to give a root..
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but cscx=y is equivalent to 1/sin x=y?
yeah
OK, that makes more sense now :)
You just sketch both sides then get the intersection
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