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Computer Science 22 Online
OpenStudy (anonymous):

find the inverse of f(x)=(x+1)/(x-1)

OpenStudy (anonymous):

(x+1)/(x-1)

OpenStudy (anonymous):

the same?....why?....wolfram suggests that too but it doesnt make sense :S

OpenStudy (anonymous):

well check it out.....try substituting some value......

OpenStudy (anonymous):

so if the inverse is the same...there is no inverse...the function is one to one or not?

OpenStudy (anonymous):

lol no...it is bijective......the inverse is same.....jus it is a funny case :P

OpenStudy (anonymous):

bijective?

OpenStudy (anonymous):

um ok it s one one...sry not bijective

OpenStudy (anonymous):

so it is one to one but its inverse is the same as the original...thats absurd!

OpenStudy (anonymous):

lol no.....dont get so confused.....that's not absurd...no rule that inverse should nt be the same as the function....nd wat do u say about f(x) = x

OpenStudy (anonymous):

aha...thank you very much dude!

OpenStudy (anonymous):

not a prob :)

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