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Find the derivative of the function: f(x)= ln(1/7x^2) I'm figuring that i would subtract the top of the fraction by the bottom, but then I get stuck as to how to get the derivative.. so confusing
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2/x
\[\large f(x)= \ln(\frac {1}{7x^2})\] is this your function?
@dpaInc yep
wait its 7x^2 lol
f(x) = ln1 - ln(7x^2) f'(x) = -[7x^2]'/[7x^2] = -14x/(7x^2) = -2/x
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so ln1 = 0??
and i just take the derivative of the second part?
yep
-2/x?
yeah my online hw took that answer as correct. just trying to understand the how for my exam..
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i get the derivatives rules, but when "ln" is thrown in the mix, i get lost
should i treat ln as a type of variable? I can't wrap my head around natural log very wel
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