Question

Find the following (functions):

Answer 1

Let \(\ \huge f(x)=3+x^2+tan(\pi x/2) \), where \(\ \huge -1<x<1 \). \(\ \huge Find \) \(\ \huge f^-1(3). \)

Answer 2

That's \(\ \huge f^{-1} \).

Answer 3

0

Answer 4

How did you do that? What's confusing me is the \(\ \huge f^{-1}(3) \) part.

Answer 5

And how do you use that equation, \(\ \huge f(x) ? \)

Answer 6

Basically, you want to find \(f^{-1}(f(x))\) where \(f(x)=3\). So you just need to find a value of x such that \(f(x)=3\). Mahmit noticed that \(f(0)=3+0+\tan(0)=3\). Therefore, \(f^{-1}(3)=0\)