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int between pi and -pi (sin5xcox3x)
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\[\int\limits_{-\Pi}^{\Pi}\sin 5x \cos 3x\]
use trig identities for sin(u+v) and cos(u+v) and expand out to sin(x) and cos(x)
I understand the trig ident thus giving answer of -1/16 cos 8x -1/4 cos2x... but if its between pi and -pi isn't zero?
cos(x)=cos(-x)
cos pi and cos -pi both equal -1 ?
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so you have (1/16+1/4)*2
I have tried two different ways and get zero both ways. yes, cos(PI)=cos(-PI)=-1. That is why on the interval (-PI,PI), it yields a zero.
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