Mathematics
8 Online
OpenStudy (anonymous):
Which of the following is the solution to the equation 25^(z + 2) = 125 ?
z = 5.5
z = 3.5
z = -2.5
z = -0.5
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OpenStudy (callisto):
\[25^{z + 2} = 125\]\[5^{2(z + 2)} = 5^3\]\[2(z+2) =3\]
Can you solve it?
OpenStudy (anonymous):
im not sure how? :/
OpenStudy (callisto):
multiply (z+2) by 2, what do you get of the left side?
OpenStudy (anonymous):
2z+4?
OpenStudy (callisto):
Yes, now you have
2x+4 =3
Can you solve this?
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OpenStudy (anonymous):
i dont know the next step sorry
OpenStudy (callisto):
Subtract 4 from both sides, what do you get?
OpenStudy (anonymous):
2x=-1
OpenStudy (callisto):
Yes, now, divide both sides by 2, what do you get?
OpenStudy (anonymous):
-0.5
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OpenStudy (callisto):
Yes :D
OpenStudy (anonymous):
thank you :D
OpenStudy (callisto):
Welcome!!!
OpenStudy (anonymous):
hey can i ask you something
OpenStudy (callisto):
Yes?
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OpenStudy (anonymous):
i get all the steps but i was just wondering how u got 52(z+2)=53
2(z+2)=3 that part i didn't understand.
OpenStudy (callisto):
\[25 = 5 \times 5 = 5^2\]and \[125 = 5 \times 5 \times 5 =5^3\]
OpenStudy (anonymous):
ohhhhhhhh ok now i get it :]
OpenStudy (anonymous):
thanks
OpenStudy (callisto):
And the question is
\[25^{z+2} = 125\]So, \[(5^2)^{z+2} = 5^3\]By properties of exponential functions, \[5^{2(z+2)} = 5^3\]
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OpenStudy (callisto):
Welcome!~