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Mathematics 18 Online
OpenStudy (anonymous):

Last question for the school year! Please help ASAP!!

OpenStudy (anonymous):

OpenStudy (anonymous):

To find the length of a vector, simply take the square root of the sum of the squares, \(\ \huge \sqrt{4+16+25} \). This, \(\ \huge \sqrt{45} \), or \(\ \huge 3\sqrt{5} \). Does that make sense to you?

OpenStudy (anonymous):

so it would be \[3\sqrt{5} \right?\]

OpenStudy (anonymous):

Length of vector: \(\ \huge \sqrt{x^2 + y^2 + z^2} .\)

OpenStudy (anonymous):

Yes, \(\ \huge 3\sqrt{5} \).

OpenStudy (anonymous):

Thank you!!

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