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Mathematics 21 Online
OpenStudy (anonymous):

Write a recursive formula for the sequence 15, 26, 48, 92, 180, …. Then find the next term.

Parth (parthkohli):

\(\Large \color{midnightblue}{\rightarrow (2*180) - 4 }\) We are essentially doubling the number and subtracting that by 4.

Parth (parthkohli):

Wait, let me find the formula.

Parth (parthkohli):

\(\Large \color{midnightblue}{\rightarrow n_{t} = 2(t - 1) - 4 }\)

Parth (parthkohli):

I mean 2(n - 1), I guess.

Parth (parthkohli):

Ask satellite.

OpenStudy (anonymous):

\[a_n=2 a_{n-1}-4\] i think is what you mean to write

OpenStudy (anonymous):

no you have it correct

Parth (parthkohli):

Partially correct.

Parth (parthkohli):

I didn't attach 2n

OpenStudy (anonymous):

just need to write the previous term as \[a_{n-1}\] not \[2(n-1)\]

OpenStudy (anonymous):

thank you everyone 4 helping me

Parth (parthkohli):

So, the correct formula is: \(\Large \color{midnightblue}{\rightarrow n_{t} = 2n_{t - 1} - 4 }\)

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