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Mathematics 18 Online
OpenStudy (anonymous):

Evaluate the expression for x = 3 and y = 6. 5(x^2 + y) + y^2

Parth (parthkohli):

\(\Large \color{midnightblue}{\rightarrow 5(3^2 + 6) + 6 }\) \(\Large \color{midnightblue}{\rightarrow 5(9 + 6) + 6 }\) \(\Large \color{midnightblue}{\rightarrow 5(15) + 6 }\) \(\Large \color{midnightblue}{\rightarrow 75 + 6 }\) \(\Large \color{midnightblue}{\rightarrow 81 }\)

Parth (parthkohli):

You just have to replace the variables with the constants given.

OpenStudy (anonymous):

A. 72 B. 87 C. 96 D. 111

Parth (parthkohli):

Actually you'd add 36, so 30 more. That'd make 111.

OpenStudy (anonymous):

that's why i was confused lol

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