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x^4/9 times x^2/3
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\[\Huge x^{\frac49+\frac23}\]
huh??
x^10/9
how did you get that answer phemo01?
\[\Huge x^a \times x^b = x^{a+b}\]that's the formula.
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oh thanks :)
Welcome.
yeah he's right...x^(4+6)/9 = X^10/9
this is question of indices and exponents whose three laws are \[a ^{x}*a^{y}= a ^{x+y}\] \[a ^{x}/a ^{y}= a ^{x-y}\] \[( a ^{x})^{y}=a ^{x*y}\] these are the formulas use these formulas to solve
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