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6-2(square root)3n = 0
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\[\large 6 - 2\sqrt{3n} = 0?\]
yaa
okay...step 1: add \(2\sqrt{3n}\) to both sides to make it positive
step two?
divide both sides by 2
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so it's just \(\sqrt{3n}\)on one side
then its \[3 = \sqrt{3n}\] right?
yep! square both sides to get n out of the root
show meeee
\[(3)^2 = (\sqrt{3n})^2\] the square root will cancel \[9 = 3n\] got it?
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yeah ! Thank youuu
last step is to divide by 3 :D
i know that :) lol
good ^_^
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