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Mathematics 17 Online
OpenStudy (anonymous):

solve log2(3x+1)=4

OpenStudy (anonymous):

transform it into an exponential equation

OpenStudy (anonymous):

how do i do that?

OpenStudy (anonymous):

log2(3x+1)=4 means that: 10^4=2(3x+1)

OpenStudy (anonymous):

@luisrock2008 is that: \[ \log_2(3x+1)=4\\ \text{or}\\ \log2(3x+1)=4? \]

OpenStudy (anonymous):

d91196 where do you get the 10 from

OpenStudy (anonymous):

@nbouscal its the first one

OpenStudy (anonymous):

If the 2 was for log base 2 then: then: 2^4=3x+1

OpenStudy (anonymous):

Okay, \(\log_2(3x+1)=4\) means: \(2^4=3x+1\). That you can solve by just calculating \(2^4\) and then solving normally.

OpenStudy (anonymous):

You ok from there?

OpenStudy (anonymous):

so does x=5

OpenStudy (anonymous):

Yep

OpenStudy (anonymous):

k

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