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solve log2(3x+1)=4
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transform it into an exponential equation
how do i do that?
log2(3x+1)=4 means that: 10^4=2(3x+1)
@luisrock2008 is that: \[ \log_2(3x+1)=4\\ \text{or}\\ \log2(3x+1)=4? \]
d91196 where do you get the 10 from
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@nbouscal its the first one
If the 2 was for log base 2 then: then: 2^4=3x+1
Okay, \(\log_2(3x+1)=4\) means: \(2^4=3x+1\). That you can solve by just calculating \(2^4\) and then solving normally.
You ok from there?
so does x=5
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Yep
k
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