Question

solve 3x^2 + 4x = 2 using quadratic formula

Answer 1

\[-b +- \sqrt{a^2 - 4ac} /2\]

Answer 2

\[-4 +- \sqrt{16 - (-24)}\]

Answer 3

4 +- √40
--------
2a

4 +- 6.32
--------
6

Answer 4

@jazy Well... quadratic formula is
\[x= \frac{-b \pm \sqrt {b^2 - 4ac}}{2a}\]

Answer 5

4 + 6.32 = 10.31 /6 = 1.72

Answer 6

Thats what I meant:)

Answer 7

Thank you guys for helping!

Answer 8

4 - 6.32 = -2.32 /6 = -0.38

Answer 9

a =3
b=4
c=-2
in this case, so, it becomes
\[x= \frac{-4 \pm \sqrt {4^2 - 4(3)(-2)}}{2(3)}\]

Answer 10

Your solutions are
(0, 1.72) and (0,-.38)
if Im not mistaken.

Answer 11

@Callisto how can I type formulas on here?

Answer 12

Use ''equation''
fraction -> \frac{x}{y}

Answer 13

I mean how do you write for example the quad formula? I've tried but idk how:/\[x = (-b +- \sqrt{b^2 - 4ac}) /2\]

Answer 14

/2a

Answer 15

lol
\frac {-b \pm \sqrt{b^{2} -4ac}}{2a}