radioactive decay problems:
(see attached file)

Question

radioactive decay problems: 
(see attached file)

anonymous · Answer

attachment

myininaya · Answer

@kryten Please explain your answers.

anonymous · Answer

thejoshfish you substract numbers and write down what you have left in this case 210-206 = 4
84-82 = 2 
so it is 
$$_{2}^{4}He$$

anonymous · Answer

so how about this: 
where would you subtract

anonymous · Answer

@Kryten

myininaya · Answer

@kryten tell me if I'm right...
All you have to do
is 
252-something=4
98-something=2

Figure out what those somethings are

myininaya · Answer

What I think that is a little wrong
I looked at it wrong

anonymous · Answer

yes you are right so when you get "something" in myininaya's equations you look at periodic table of elements, and look i have one just in my lap it is very old but will serve the purpose:
Cm - Curium

myininaya · Answer

Ok great :)

myininaya · Answer

I know no chemistry . lol.

anonymous · Answer

bu in this case equation would better go like this
252-4 = something
98-2=something

myininaya · Answer

then equations are
a+c=d
b+d=f 
?

myininaya · Answer

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