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Mathematics 15 Online
OpenStudy (anonymous):

solve lnn3x+ln2x=9

OpenStudy (campbell_st):

this can be simplifed to \[\ln(3x \times 6x) = 9\] or \[\ln(6x^2) = 9\] you now need to raise each to a power of e \[e^{\ln(a)} = a\] so \[6x^2 = e^9\] you should now be able to solve for x

OpenStudy (anonymous):

I'm not. Do i divide e^9 by 6

OpenStudy (campbell_st):

thats the 1st step

OpenStudy (anonymous):

square root of 9 then

OpenStudy (campbell_st):

remember e^9 is just a number

OpenStudy (campbell_st):

\[x=\pm \sqrt{\frac{e^9}{6}}\]

OpenStudy (anonymous):

oh, thanks

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