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Transform the following polar equation into an equation in rectangular coordinates: r=2 cos theta x = 2 (x-1)^2+y^2=1 y = 2x x + y = 2
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r=2 cos theta multiply r to both sides: r^2 = 2 rcos(theta) since r^2 = x^2 + y^2 and x = rcos(theta), x^2 + y^2 = 2x can you take it from here?
Yes thank you
yw
I thought i understood it but i still need the answer to make sure
in polar x= rcostheta and y = rsintheta
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you can just sub those in and your good to go
are you able to get here: x^2 + y^2 = 2x ?
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