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Use summation notation to write the series 49 + 54 + 59 +... for 14 terms.
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@campbell_st and @ParthKohli i need ur help again
and explanations
Wait, I know this one. Can you wait for a sec? Have to refresh
@ParthKohli yeah sure
well find the common difference... then make the adjustment... looks like 5n + 44
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\[\Large \sum_{a = 1}^{14th}\]
Replace 14th with 14th term..
parth you don't need 14th... its just 14.... the terminating value of n
Oh yes.
\[\sum_{n=1}^{14} (44+5n)\] or (49+59)
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(49+5n) not 59
|dw:1337151123965:dw|
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