Find the smaller angle between vectors a and b a= <3,2,1> b=<-3,0,-1>
so this is what i have so far, and i'm not sure if i did it correctly or not... aob = ||a|| ||b|| CosTheta -10 = \[-10= \sqrt(14)\sqrt(10) Cos \theta\]
so i get \[\cos \theta = -10/ 11.8\]
if i arctan this i get 32.4, but apparently that's not the right answer? o.O
i mean, arc cos lol
yes.you are right.
my teacher marked it wrong :( i think i may have done something wrong somewhere? o.O
i got 32.06 degrees
i think you may have done some calc. mistakes
wait, i got 32.06 on my calculator lol but marked down 32.4 would she seriously mark me off 3 points because i'm off .34 points..???
wait isnt aob = -8 ? no - forget that -10 is right
yea 32.06 is correct
3 points off is a bit harsh - marks are usually awarded for method and accuracy and you had the method right
is it the smaller of the two angles? maybe that's why it's wrong? is it possible to have a smaller angle?
no.the other one is |dw:1337165920119:dw|
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