Question

What is the equation in standard form of the line through (4,1) and (-2,3) help!!!

Answer 1

x - 3y = 1

Answer 2

thnx but can u plz tell me how u got that?

Answer 3

First, find the gradient using:
\[m = (y_{2} - y_{1})/(x_{2} - x_{1})\]\[m = (3 - 1) / (-2 -4)\]\[m = 1/3\]
Using the formula for finding eqn of a line:
\[y - y_{1} = m(x - x_{1})\]\[y - 1 = 1(x - 4)/3\]\[y = 1(x)/3 - 1/3\]
Expressing in standard form:
\[x - 3y = 1\]

Answer 4

I am new to this site so pardon my equations. Learning how to use the equation editor

Answer 5

ooo thank you!!!!!!!

Answer 6

You welcome :)