Question

\[X:\sqrt{3x} +9 =-6\]

Answer 1

1) subtract 9 from both sides
2) square both sides
3) divide both sides by 3

Answer 2

okay hold on I will try it

Answer 3

let me know if/where you get stuck

Answer 4

ok

Answer 5

I dont think there is a solution

Answer 6

hm...
could you show your steps?
what do you have after the first step?

Answer 7

thanks hold on im really bad at math great at english lol

Answer 8

i got 9

Answer 9

for the final answer?
no, that's not right I don't think

just subtract 9 from both sides first
what's left?

Answer 10

3

Answer 11

where did x go?\[\sqrt{3x}+9=-6\]subtracting 9 from both sides gives\[\sqrt{3x}+\cancel9^0-\cancel9^0=-6-9\]\[\sqrt{3x}=-15\]if this is novel to you I think you need to step back to the basics of doing arithmetic on each side of the euation

the next step is to square both sides
remember that\[(\sqrt x)^2=x\]and don't forget tot square \(both\) sides

Answer 12

the choices I have for answers are 9, 1/9, 81, no real solution