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Given the triangle below, what is sec∡C?
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sec is inverse of the cos where cos=adjacent/hyp. so sec=hyp/adj
im stuck between two answers
i did the pythogream theorem
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but that is where i am stuck i got 33 but i have to square root it or simplify it
u know where is adjacent and where is Hypotenuse
yes the adjacent is 4 and the hypthenuse is 7
Thats totally right ,so Cos(c) = Adjacent / Hypotenuse Sec(c) = Hypotenuse / Adjacent = 7/4
right but can you help me determine the answer
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neither this nor this ,check the answers :)
okay
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