Question

\[X: \sqrt{3x}+3=5-x\]

Answer 1

you need solving for x , yes ?

Answer 2

yes

Answer 3

in first step add to both sides -3

Answer 4

i am going to make a guess that it is
\[\sqrt{x+3}=5-x\]

Answer 5

no its the way i posted it

Answer 6

sqrt3x +3 -3 =5-3-x
sqrt3x =2-x so now squaring the both sides what will get ?

Answer 7

then i will be quiet, jhonyy has it

Answer 8

so than

3x=(2-x)(2-x) can you continue ?

Answer 9

no I'am totally lost

Answer 10

where and why ?

Answer 11

I'm going to fail this class
I'm not good in math at all
can you have 2 answers

Answer 12

I end up w 2 or 11

Answer 13

so 3x=x^2 -4x +4
x^2 -7x +4=0
x_1,2 =(7+/- sqrt(49-16))/2 =(7+/-sqrt33)/2

Answer 14

ok ?

Answer 15

No I guess Im not going to get it
my choices are 2, 11, or 2 and 11 or no solution

Answer 16

It is multiple choice

Answer 17

so if you will check it with these roots will get those right ?

Answer 18

for 2 you will get 6=0

Answer 19

well its a b c or d
it is multiple choice
so then there is no real solution

Answer 20

given the are A of a circle the formula r= \[\sqrt{a/3.14}\] can be used to calculate the radius of the circle. Fine the area when the radius is 18 8.2 cm

Answer 21

area of a circle = pir^2 so from this result that r=sqrt(A/pi) so what you nhave wrote there yes is right sure