Solve for x:
have you had a go? where did you get stuck?
I think you find the common denomitaor first?
Im not good with algebra. :/
you could, and thats absolutely correct in some cases. in this case its easier, we just need to multiply a few things i'll guide you through :)
Thanks
\[\frac{3x - 5}{4} = \frac{5x - 11}{6}\] usually its the case that fractions are annoying in equations. we want to get them out of the way so we can start solving. first of all multiply both sides by the left denominator 4 \[\frac{3x - 5}{4} \times 4 = \frac{5x - 11}{6} \times 4\] \[\frac{4(3x - 5)}{4} = \frac{4(5x - 11)}{6} \] the 4's on the left now cancel, leaving: \[(3x - 5) = \frac{4(5x - 11)}{6} \] now do the same but this time with 6 \[(3x-5) \times 6 = \frac{4(5x - 11)}{6} \times 6\] \[6(3x-5) = \frac{4(5x - 11) \times 6}{6} \] \[6(3x-5) = 4(5x - 11)\] now we just solve like normal. are you ok from here?
i think . 6(3x - 5) = 4(5x - 11) would be 18x - 30 = 20x - 44?
yep :D are you ok with how i got rid of the fractions?
Yea. I think more practive and i willl get the hang of it. :)
wehn i solve for x i get -37. but thats not one of my choices
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