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Mathematics 9 Online
OpenStudy (anonymous):

honk

OpenStudy (anonymous):

First we need to figure out what direction that line is going in. I suggest letting x = t, and finding out what y and z are in terms of t. Basically we need to get a prametric form of the line so we can get the direction of it easily.

OpenStudy (dumbcow):

i agree ^^ i came up with x = 2t y = 3t-1 z = t-4 so directional vector is <2,3,1>

OpenStudy (anonymous):

sweet. now it should be clear what the answer is :)

OpenStudy (dumbcow):

@calculusnub , do you need more explanation ?

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