Question

For which value of x does the graph of y = 3x^2 - 2x - 5 cross the x-axis?

Answer 1

y = 3x^2 - 2x - 5
y = (3x-5)(x+1)
When it crosses x-axis, y=0, so put y=0 into the equation
0 = (3x-5)(x+1)
(3x-5)=0 or (x+1)=0
Can you solve them?

Answer 2

Just follow Callisto's steps and solve for x:
3x - 5 = 0
&
x + 1 = 0

Answer 3

-1?

Answer 4

Yes that's the second one.

Answer 5

-1 is one of the answers. You also need to solve (3x-5)=0

Answer 6

im confused on that 1 :S

Answer 7

3x-5 =0
3x-5 +5 = 0+5
3x = 5
\[\frac{3x}{3} = \frac{5}{3}\]
x=?

Answer 8

-2?

Answer 9

Nope :|
\[x=\frac{5}{3}\] :|