Question

A firecracker has dimensions as shown. Height is 14 cm, radius is 1 cm and slant height of the cone is 2 cm.

Paper covers the entire surface area including the cone, the lateral area and the bottom circle but does not include the tail.

What is the best approximate area of paper needed to wrap the firecracker?


(Use for . Round your answer to the nearest whole number.)

Answer 1

you have 2 different shapes. a cilinder and a cone. to calculate the whole area you will need to calculate the total area of the cilinder and the total area of the cone.

\[Acone= pi * r^2\]
\[Acilinder=2*π*r*h + 2π*r2 \]

Answer 2

\[pi=3.14\]

Answer 3

yes.

Answer 4

can you set the problum up with me?

Answer 5

yes, sure.

Answer 6

OK

Answer 7

\[Acone: 3,14*1^2\]

Answer 8

= 3.14

Answer 9

\[Acilinder=2*3,14*1*14+2*3,14*1^2\]

Answer 10

then:
Acone+Acilinder

Answer 11

and that is your answer :)

Answer 12

hold up please

Answer 13

=287.4888

Answer 14

:)

Answer 15

thats not the answrs i have. thought

Answer 16

\[100cm2 power
97cm to 2 power
91cm2 power
104cm2

Answer 17

well, those are the formulas :x

Answer 18

didd i do the math wrong? can yuu coculated them 2

Answer 19

the answer is 97.2

Answer 20

see

Answer 21

yees, i just told you the answer lol

Answer 22

no...! lol jk

Answer 23

haha