Question

Compute the following (i)^(-n) please show work so I can understand how to get the answer. Thank you

Answer 1

\[b^{-n}=\frac{1}{b^n}\]

Answer 2

is \(i=\sqrt{-1}\) in this case?

Answer 3

no, I dont think so

Answer 4

then by definition
\[i^{-n}=\frac{1}{i^n}\]there is no other work to be done

Answer 5

We have to be able to express it in a+ib form