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Mathematics 6 Online
OpenStudy (anonymous):

simplify f(x)= (2x^2+3x+1) then using complete sentences explane why f(1)=2, f(0)=1, and f(-1)=0, yet f(-1/2) is undefined, please show work :)

OpenStudy (eyust707):

do you know what we mean by "f(1)"

OpenStudy (anonymous):

no

OpenStudy (eyust707):

f(1) means: "plug a 1 in for x"

OpenStudy (eyust707):

what does that equation equal when we put a 1 in for x?

OpenStudy (anonymous):

its over 2x+1 i forgot that

OpenStudy (eyust707):

okay..

OpenStudy (eyust707):

same notation applies

OpenStudy (eyust707):

what does that equation equal when we plug a 1 in for x?

OpenStudy (anonymous):

the x in f(x) is the plug in for all the x's i know

OpenStudy (eyust707):

yes change all the x's for 1

OpenStudy (eyust707):

then do easy math to come up with a number

OpenStudy (anonymous):

i still cant simplify it

OpenStudy (eyust707):

what do you have?

OpenStudy (anonymous):

have what?

OpenStudy (eyust707):

What equation are you having trouble simplifying?

OpenStudy (anonymous):

the one in the questain next to the word simplify over the other numbers i said i forgot

OpenStudy (eyust707):

did you plug in a 1 for x?

OpenStudy (anonymous):

that wony simplify it -___-

OpenStudy (eyust707):

did you try?

OpenStudy (eyust707):

because i assure you it will

OpenStudy (anonymous):

its 6 nut thats an answer not a simplify

OpenStudy (eyust707):

remember its all over.. 2x+1

OpenStudy (eyust707):

and when you plug a 1 in for x on the bottom part you get 3

OpenStudy (eyust707):

6/3 is 2

OpenStudy (eyust707):

which is why f(1) = 2 !!!

OpenStudy (anonymous):

yah and...

OpenStudy (eyust707):

that is the very first part of the question you posted and asked for help on

OpenStudy (eyust707):

if you do the same for 0 you get 1

OpenStudy (anonymous):

itds noy simplixied

OpenStudy (eyust707):

the number "2" is as simple as it gets!

OpenStudy (eyust707):

now the next part is to try and do that for -1/2

OpenStudy (anonymous):

\[\large f(x) = \frac {2x^2+3x+1}{2x+1}\] i'm just clarifying the function.... :)

OpenStudy (eyust707):

sweet!

OpenStudy (eyust707):

if you would like to finish the problem try and plug in -1/2 for x..

OpenStudy (eyust707):

you wil find that you get 0 in the denominator

OpenStudy (eyust707):

anything over 0 is undefined

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