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g(x) = 4x(x^2 − 4x − 3) (a) Find all the real zeros of the polynomial function.
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can't you factor out (x^2 − 4x − 3)?
Set it =0 and solve
I"m having a difficult time with it for some reason. it's not coming to my head.
Well, the trinomial will not factor so you will have to use the quadratic formula to find the zeros of that factor.
\[4 x \left(x^2-4 x-3\right)=0\]
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So you have 4x=0 or x^2-4x-3=0 x=0 and solve the quadratic with the formula.
\[x=0\text{ or }4 x^2-16 x-12=0\]
OH RIGHT. i totally forgot about the quad formula, lol.
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