Question

4x/3 - (x-1)/2 = 1

Answer 1

multiply every term by 6

\[\frac{6\times4x}{3}-\frac{6\times(x -1)}{2} = 6\]


then cancelling common factors gives

\[8x -3x + 3 =6 \]

5x = 3

x = 5/3

Answer 2

for the \[\left(\begin{matrix}x-1 \\ 2\end{matrix}\right)\] isnt it supposed to be 3x-3?

Answer 3

Rubie it would be but there is a double negative which makes it a positive

Answer 4

but 6/2 is 3 and 3 is a tripe so it should be negative again

Answer 5

*triple

Answer 6

@Rubie, @campbell_st is correct.

From basic mathematics,
-2 x -2 = 4
-2 x 2 = -4
-2 + -2 = -4
-2 + 2 = 0
2 - (-2) = 4

One thing you should remember is that, negative negative always evaluates to positive.
Hence
\[\frac{-6x + 6}{2}\]
So 2 divides -6x = -3x and 2 divides 6 = 3
That's why you see -3x + 3

Answer 7

ahhhh okai thank you all of youu