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Evaluate the expression for the given values of the variables. 4t + 2u^2 – u^3; t = 2 and u = 1
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Substitute and solve 4t + 2u^2 – u^3 4(2) + 2(1)^2 – (1)^3
What do you get?
how exactly do you substitute ?
its because t=2 and u=1, So in our equation, 4t + 2u^2 – u^3 we can replace the numbers with the alphabets, 4(2) + 2(1)^2 – (1)^3
i mean we can replace the alphabets with the numbers,
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Then ?
4(2) + 2(1)^2 – (1)^3 8+2-1=?
so the answers 10 ?
8+2-1=? eight plus two minus one equals?
9
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