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OpenStudy (anonymous):
whoever knows how to do these please help, preferably someone knew that can show me all the work to solve these. 4x+y=18 x=y-3
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OpenStudy (kymber):
What're you supposed to do?
OpenStudy (anonymous):
solve by using the substitution method
OpenStudy (asylum15):
Put x=y-3 into 4x+y=18 So 4(y-3) + y =18 Multiply out and I'm guessing you'll get a quadratic equation which you can solve for 2 x values.
Parth (parthkohli):
It's already given that x = y - 3 So, 4x + y will be 4(y - 3) + 3
OpenStudy (asylum15):
Nevermind my reply, you'll get 4y - 12 + y = 18 5y = 18 + 12 5y = 30 y = 6
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