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\[\int\limits_{-T/2}^{T/2}m2(t)\cos(4piFt)dt \]
F is a constant right?
I'll assume F is a constant for now letting u = 2Ft should yield: \[m/(2*F^2)\int\limits_{-TF}^{TF} ucos(2pi u)du\] which should be easier to integrate no?
dear f is constant
@ mathmuse dear m is a function of t .
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what's the 2?
2 is power of m (t)
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