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find the polynomial f(x) that has the roots of -3, 5, of multiplicity 2
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\[(x+3)^2 (x-5)^2 \]
how would you verify the zeros of f(x)
because @FoolForMath wrote it in factored form, isn't it obvious?
where does the multiplicity 2 come in
that's the number of times each factor appears (it's exponent)
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ok i understand that but how do I verify the zeros?
solve this equation: \[\large (x+3)^2 (x-5)^2=0\] the solution(s) to that equation are your zeros.
stick in a -3 then stick in a 5. you see the equation holds true.
ok thanks so much
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