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find the derivative of the function cosx
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-sinx
if you remember cos always goes to -sin when you differentiate then think of x as a functon so you have f(x)=x differentiate you get f'(x)=1 1 goes infront of sin you get -sinx
k i understand thnx. but is there any way to solve it using trig formula
you mean starting with the difference quotient?
I have to go the derivation is long, and relies on knowing \[\lim_{x\to0}\frac{\sin x}x\text{ and }\lim_{x\to0}\frac{\cos x-1}x\]and sum of angles trig identity
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here is a link for the proof of sinx the one for cos is similar enough that you should be able to use the same ideas
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