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solve for x from [0,2pi): sqrt3 tanx=1
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\[\sqrt{3}\tan x=1\]
divide by sqrt3 both sides: tanx = 1/sqrt3 = (sqrt3)/3 x is a common angle... [HINT]
its 30 degrees right?
yes.. but there's another one... btw... they asked for radians so 30 degrees = pi/6
it's in quadrant 3 that's where tan is positive.
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7pi/6?
yes...
good job kaisan... :) btw... maybe you should write out the tangents of each of those common angles on your unit circle... ... just a suggestion.
i'm not really good with tangent, i always get things mixed up
and that's why u should write it on your unit circle...:)
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