Question

last one.
What is the sum of the arithmetic sequence 140, 134, 128..., if there are 33 terms?

1,364
1,408
1,452
1,496

Answer 1

Okay, we know d = 134 - 140 = -6
Applying the same reasoning as before, the sum of all the terms will be
\[33a_1 + {{32(33)} \over 2}d = 33*140 + 528*(-6) = 1452\]

Answer 2

thanks for all your help!!!1