Question

What are the possible number of positive, negative, and complex zeros of f(x) = –2x3 – 5x2 – 6x + 4 ?

Answer 1

well if you had \[x^2\]
how many solutions would you be able to find

Answer 2

Two sign changes so possibly 2 or 0 positive zeros.
Replace x with -x. You will get: -2x^3-5x^2+6x+4
One sign change so possible 1 negative zero.

Answer 3

It's of degree 3 so possibly 2 complex zeros. Couldn't be 3 because they come in pairs.