simplify the inverse trig function with answers (-inf, +inf): cos(inverse)(sqrt3/2)
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OpenStudy (anonymous):
answers from \[(-\infty,\infty)\] equation is \[\cos^{-1} (\sqrt{3}/2)\]
OpenStudy (anonymous):
Cosine takes in angles and gives out a ratio of sides.
Inverse cosine goes backwards. It takes in a ratio of sides, and it tells you what angles have that ratio.
OpenStudy (anonymous):
And cos is a/h, so just make a triangle with those sides, then figure out what the angle is.
OpenStudy (anonymous):
still have your unit circle or you got it memorized?
OpenStudy (anonymous):
I wouldn't use the unit circle here, since the hypotenuse is 2.
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OpenStudy (anonymous):
But I suppose you could.
OpenStudy (anonymous):
sqrt3/2 is a cos/sin of one of the common angles though right?
OpenStudy (anonymous):
probably... maybe. Lols.
OpenStudy (anonymous):
i have the unit circle i know most of it by heart
OpenStudy (anonymous):
ok...
cos(what angle) = sqrt3/2 ???
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OpenStudy (anonymous):
wait cos is the x-value right? o.o
OpenStudy (anonymous):
correct
OpenStudy (anonymous):
30 degrees?
OpenStudy (anonymous):
yes... but what else?
OpenStudy (anonymous):
300 degrees?
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