simplify the inverse trig function with answers (-inf, +inf): cos(inverse)(sqrt3/2)
answers from \[(-\infty,\infty)\] equation is \[\cos^{-1} (\sqrt{3}/2)\]
Cosine takes in angles and gives out a ratio of sides. Inverse cosine goes backwards. It takes in a ratio of sides, and it tells you what angles have that ratio.
And cos is a/h, so just make a triangle with those sides, then figure out what the angle is.
still have your unit circle or you got it memorized?
I wouldn't use the unit circle here, since the hypotenuse is 2.
But I suppose you could.
sqrt3/2 is a cos/sin of one of the common angles though right?
probably... maybe. Lols.
i have the unit circle i know most of it by heart
ok... cos(what angle) = sqrt3/2 ???
wait cos is the x-value right? o.o
correct
30 degrees?
yes... but what else?
300 degrees?
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