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OpenStudy (anonymous):
OpenStudy (amistre64):
hmm, displacement/time = average velocity is what your last question i helped out stated.
integration gives us the area under a curve, which is also a definition of displacement
OpenStudy (anonymous):
OpenStudy (amistre64):
\[2\int_{0}^{1}\sqrt{1-x^2}dx\] is my idea
OpenStudy (anonymous):
i got this answer from a site but can not understand it
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OpenStudy (amistre64):
ok, thats using the standard definition of displacement
OpenStudy (amistre64):
notice that from start to finish the thing is only displaced by 2 units, the negative is a direction .. downward
OpenStudy (amistre64):
displacement / time = -2/1
OpenStudy (anonymous):
but it is given only 1 m ? how are -2 m there ?
OpenStudy (amistre64):
its a semicircle with a radius of 1m
the diameter of the circle measures 2m in a down direction, so -2m
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OpenStudy (anonymous):
oh yes thanks thanks thanks thanks thanks a lot :)))))))))))))))))))))))) gr8 help amsitre , i think u deserve the word SIR
OpenStudy (amistre64):
i spose, its on all the letters i get from the collection agencies :)