help me in this question of vectors
hmm, displacement/time = average velocity is what your last question i helped out stated. integration gives us the area under a curve, which is also a definition of displacement
\[2\int_{0}^{1}\sqrt{1-x^2}dx\] is my idea
i got this answer from a site but can not understand it
ok, thats using the standard definition of displacement
notice that from start to finish the thing is only displaced by 2 units, the negative is a direction .. downward
displacement / time = -2/1
but it is given only 1 m ? how are -2 m there ?
its a semicircle with a radius of 1m the diameter of the circle measures 2m in a down direction, so -2m
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nice
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