Question

solve
3n^2=-6n-2

Answer 1

-1+1/3^0.5 and -1-1/3^0.5

Answer 2

put everything on one side

\[3n^2 +6n + 2 = 0\]

this quadratic can't be factorised

so use the gerneral quadratic formula

a = 3 b = 6 and c = 2

\[n = \frac{-6 \pm \sqrt{6^2 - 4\times3\times2}}{2\times3}\]

will give

\[n =\frac{ -3 \pm \sqrt{3}}{3}\]

Answer 3

thanks