Question

Pablo rolled a standard die 30 times. He got a 1 eight times. How does this result compare to the expected results? Explain.

Please explain (confused) :S

Answer 1

@dpaInc Need ur help!! lol

Answer 2

A standard die has 6 sides. You expect each side to have an equal chance of landing face up.


So the probability of getting any face is 1/6


So the probability of getting a 1 showing face up is 1/6


Out of 30 times, you'll land a "1" 30(1/6) = 30/6 = 5 times


So Pablo rolled a "1" three more times than expected.

Answer 3

why 3 more times??

Answer 4

because we expect to roll a "1" five times

we expect to roll a "2" five times

...

etc

for all 6 numbers

So each number should show up 5 times. There are 6 numbers, which totals to 5*6 = 30 rolls.

Answer 5

ohhhhh ok!

Answer 6

But he rolled a "1" 8 times, which is 8-5 = 3 more than expected


It's not like it's impossible, it's just that the average number of rolls should be 5.

Answer 7

ok! perfectoo lol

Answer 8

lol awesome