Question

plzz check.

Answer 1

#include<iostream>
using namespace std;
class Operation
{
private:
int answer;
int numberA;
int numberB;
public:

int addition(int numberA,int numberB);
int subtraction(int numberA,int numberB);
int multiplication(int numberA,int numberB);
int division(int numberA,int numberB);
int getNumberA();
void setNumberA(int numberA);
int getNumberB();
void setNumberB(int result);
void printOnScreen(int answer);
};
int Operation::getNumberA()
{
return numberA;
}
void Operation::setNumberA(int A)
{
numberA=A;
}
int Operation::getNumberB()
{
return numberB;
}
void Operation::setNumberB(int B)
{
numberB=B;
}
int Operation::addition(int numberA,int numberB)
{
return (numberA+numberB);
}
int Operation::subtraction(int numberA,int numberB)
{
return (numberA-numberB);
}
int Operation::multiplication(int numberA,int numberB)
{
return (numberA*numberB);
}
int Operation::division(int numberA,int numberB)
{
return (numberA/numberB);
}
void Operation::printOnScreen(int answer)
{
cout<<answer<<endl;
}
int main()
{
Operation o;
int numberA, numberB, answer, choice;
o.setNumberA(8);
o.setNumberB(7);
cout<<"Enter the choice:";
cin>>choice;
switch(choice)
{
case 1:
o.addition(numberA,numberB);
break;
case 2:
o.subtraction(numberA,numberB);
break;
case 3:
o.multiplication(numberA,numberB);
break;
case 4:
o.division(numberA,numberB);
break;
default:
cout<<"Wrong choice"<<endl;
}
o.printOnScreen(int answer);
system("PAUSE");
return 0;
}

Answer 2

about your printOnScreen method:

Shouldn't it take no arguments, and just print out the private memver `answer'? otherwise the last statement in main before system(pause) (o.printOnScreen(int answer);) is a syntax error :)

Answer 3

private member* `answer'

something like

void Operation::printOnScreen()
{
cout << answer << endl;
}

Answer 4

This is the question
Write a C++ program with multiple methods to intake the two integers and do the, Addition, Subtraction, Multiplication, and Division.
Hints: 1.Use the following class diagram for your implementation.
2.On your main method u hav to implement selection and repetition of the arithmetic operation
3.You can include any more methods if required.

Answer 5

ah I get it now. you need to either declare an answer variable to store the results of adding/multiplying/etc and supply it as an arugment to void Operation::printOnScreen(int answer), or you need to change the adding/subtracting/etc methods to change the `answer' member variable

Answer 6

Class diagram
Arithmetic
int numberA
int numberB
int answer
int addition
int subtraction
int multiplication
int division
void getAnswer
void setAnswer
void printOnScreen

Answer 7

with that diagram, it looks like you are just missing the getAnswer and setAnswer methods.

Answer 8

yep. bt am trying to include it. am totally confused.

Answer 9

something like:

int Operation::getAnswer()
{
return answer
}

void Operation::setAnswer(int answer)
{
this->answer = answer;
}

Answer 10

ya I knw that. bt it is given in the class diagram as void getAnswer.

Answer 11

that's confusing then; getter methods are supposed to return something, no? :(

Answer 12

ya u r right.
and also i dnt knw vt to include in printOnScreen() .:(

Answer 13

from your first post, your printOnScreen looks fine. when you use it in main you can do something like:

o.printOnScreen(o.getAnswer());

Answer 14

#include<iostream>
using namespace std;
class Arithmetic
{
private:
int answer;
int numberA;
int numberB;
public:

int addition(int numberA,int numberB);
int subtraction(int numberA,int numberB);
int multiplication(int numberA,int numberB);
int division(int numberA,int numberB);
int getNumberA();
void setNumberA(int numberA);
int getNumberB();
void setNumberB(int result);
int getAnswer();
void setAnswer(int result);
void printOnScreen();
};
int Arithmetic::getNumberA()
{
return numberA;
}
void Arithmetic::setNumberA(int A)
{
numberA=A;
}
int Arithmetic::getNumberB()
{
return numberB;
}
void Arithmetic::setNumberB(int B)
{
numberB=B;
}
int Arithmetic::addition(int numberA,int numberB)
{
return (numberA+numberB);
}
int Arithmetic::subtraction(int numberA,int numberB)
{
return (numberA-numberB);
}
int Arithmetic::multiplication(int numberA,int numberB)
{
return (numberA*numberB);
}
int Arithmetic::division(int numberA,int numberB)
{
return (numberA/numberB);
}
int Arithmetic::getAnswer()
{
return answer;
}
void Arithmetic::setAnswer(int result)
{
answer=result;
}
void Arithmetic::printOnScreen()
{
cout<<answer<<endl;
}
int main()
{
Arithmetic a;
int numberA, numberB, answer, choice;
a.setNumberA(8);
a.setNumberB(7);
cout<<"Enter the choice:";
cin>>choice;
switch(choice)
{
case 1:
a.addition(numberA,numberB);
break;
case 2:
a.subtraction(numberA,numberB);
break;
case 3:
a.multiplication(numberA,numberB);
break;
case 4:
a.division(numberA,numberB);
break;
default:
cout<<"Wrong choice"<<endl;
}
a.printOnScreen();
system("PAUSE");
return 0;
}

Answer 15

Bt I dnt get the expected output. Dnt knw y.:(

Answer 16

What is the output you expect?

Answer 17

as u can see I hav passed the values 8 and 7 for A and B. If my choice is 1 I should get 15 as the output. Bt I dnt get t.

Answer 18

@ajprincess ,

int Arithmetic::addition(int numberA,int numberB)

This is wrong.
a.addition(numberA,numberB);

It should be
int temp;
temp =a.addition(numberA,numberB);

Answer 19

Do you understand that you were not storing the value returnnd by " int Arithmetic::addition(int numberA,int numberB) " in a variable

Answer 20

I hav already declared answer in my main method.
Nw I wrote this
answer=a.addition(numberA,numberB)
It's correct nw. Isnt t?

Answer 21

Nope @ajprincess , it should be
a.answer=a.addition(numberA,numberB);

answer is private member function of Arithmetic

Answer 22

BUt why did you declare another answer varible in main () ??

Answer 23

If I change it like this I get an error saying that answer is private.

Answer 24

Got it. It should be

answer=a.addition(numberA,numberB);
setAnswer(answer);

Now it should be fine

Answer 25

bt it reports an error as answer undeclared

Answer 26

Sorry @ Ajprincess. It should be

answer=a.addition(numberA,numberB);
a.setAnswer(answer);

Answer 27

bt I wrote it as a.setAnswer(answer)

Answer 28

LOl @ajprincess . I just noticed another mistake.
int temp, temp1;
temp=getNumberA();
temp1=getNumberB();
answer=a.addition(temp,temp1);
a.setAnswer(answer);

Answer 29

if I make this many mistakes dnt knw hw I am gonna finish this within 45mints.
Thanxxxxxxx a lot. @Shivam_bhalla. U r so helpful.

Answer 30

LOL. No problem. I also learnt by making these mistakes :P

Answer 31

U too @agdgdgdgwngo are really helpful. Thanxxxxx a lot.

Answer 32

in my question repetition of arithmetic operation is askd to b implemented. Hw wud i do that?@Shivam_bhalla

Answer 33

@shivam_bhalla

Answer 34

I was busy at another question. If your question is asking for repeting of arithmetic operation then you can add the (Number 1 +Number 2)+number 1

Answer 35

can u please show with my function declarations?

Answer 36

@ajprincess , why don't you try by yourself?. Learn by trying on your own. You will get the logic. Then try to implement that logic :D

Answer 37

k thanxxxx a lot. @shivam_bhalla

Answer 38

np ;). Remember. Computer is a easy subject. Just practice it on your own by making your own programs :)

Answer 39

Sure.:)