Question

Find the product: (4y + 3)(4y − 3)

Answer 1

16y^2 -9

Answer 2

@careless850 Use the relation
\[\huge (a+b)(a-b)=a^2-b^2\]

Answer 3

@ash2326 What relation would I use for ones like this? --> Factor Completely: x2 + 16

Answer 4

\[ x^2+16\]
It can't be factored more, unless complex no. are involved!! I suppose you don't know complex no., do you?
But there is an alternate form
\[(x+4)^2-8x\]

Answer 5

I don't know complex no.
And I'm guessing that this would be prime?