Question

okay, I am having trouble with this will sumone explain it to me?
Enter the quadratic equation in standard form.
x^2 -5x-5=2x+3

Answer 1

The standard form of a quadratic equation is basically:

\(\Large \color{MidnightBlue}{\Rightarrow ax^2 + bx + c = 0 }\)

Bring 0 on one side.

Answer 2

From both sides, subtract 2x and 3 to bring it to the standard form.

Answer 3

x^2 -5x-5=2x+3
x^2 -5x -5 -2x=2x+3-2x
x^2 -7x-5=3
x^2 -7x -5 -3 = 3-3
x^2 -7x -8=0

Answer 4

Well the standard form for a quadratic equation is Ax^2+Bx+C=0 where A,B,C are constants.

For your problem, bring all the parts of the equation on one side and do the following,
x^2 -5x-5=2x+3
x^2 -5x -5 -2x=2x+3-2x
x^2 -7x-5=3
x^2 -7x -5 -3 = 3-3
x^2 -7x -8=0