Question

i need help with this problem... could someone help me with the steps please...Find a quadratic equation, with integer coefficients, that has solutions{3i,-3i} .

Answer 1

\(\Large \color{MidnightBlue}{\Rightarrow x^2 + 0x + 0 = -1 }\)

The most basic form.

Answer 2

it is a(x-3i)(x+3i) when a is any integer
so the quardratic equa is a(x^2+9)

Answer 3

You can add a more of bits.

\(\Large \color{MidnightBlue}{\Rightarrow x^2 + 0x + 1 = 0 }\)

Answer 4

Wait, its 3i..

Answer 5

I guess you can manage the rest.

Answer 6

it's wrong 'cuz -3i*3i has only one answer
= -9i^2 = -9*-1 = 9

Answer 7

i*i = -1

Answer 8

get it?

Answer 9

yes i remember that now :) thanks!!