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i need help with this problem... could someone help me with the steps please...Find a quadratic equation, with integer coefficients, that has solutions{3i,-3i} .
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\(\Large \color{MidnightBlue}{\Rightarrow x^2 + 0x + 0 = -1 }\) The most basic form.
it is a(x-3i)(x+3i) when a is any integer so the quardratic equa is a(x^2+9)
You can add a more of bits. \(\Large \color{MidnightBlue}{\Rightarrow x^2 + 0x + 1 = 0 }\)
Wait, its 3i..
I guess you can manage the rest.
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it's wrong 'cuz -3i*3i has only one answer = -9i^2 = -9*-1 = 9
i*i = -1
get it?
yes i remember that now :) thanks!!
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