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x^2+4x+4x+16=8 enter the quadratic equation in standard form.
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x^2+8x+8=0
The standard form of any quadratic equation is \[ax^2+bx+c=0\]
Where a,b,c are constants
hey the left side can be factorised as (x+4)^2=8 x+4=\[\[\pm\]x+4=2\sqrt{2}\]
ofcourse a cannot be equal to 0
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sry typing error \[x+4=\pm \sqrt{8}\]
@vamgadu , I think @Astemmene is looking for standard form of quadratic equation.
oh i dint look and you caught me!!:P
np :)
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